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SubjectRe: regression in page writeback
On Wed, 23 Sep 2009 09:32:36 +0800 Wu Fengguang <fengguang.wu@intel.com> wrote:

> On Wed, Sep 23, 2009 at 09:28:32AM +0800, Andrew Morton wrote:
> > On Wed, 23 Sep 2009 09:17:58 +0800 Wu Fengguang <fengguang.wu@intel.com> wrote:
> >
> > > On Wed, Sep 23, 2009 at 08:54:52AM +0800, Andrew Morton wrote:
> > > > On Wed, 23 Sep 2009 08:22:20 +0800 Wu Fengguang <fengguang.wu@intel.com> wrote:
> > > >
> > > > > Jens' per-bdi writeback has another improvement. In 2.6.31, when
> > > > > superblocks A and B both have 100000 dirty pages, it will first
> > > > > exhaust A's 100000 dirty pages before going on to sync B's.
> > > >
> > > > That would only be true if someone broke 2.6.31. Did they?
> > > >
> > > > SYSCALL_DEFINE0(sync)
> > > > {
> > > > wakeup_pdflush(0);
> > > > sync_filesystems(0);
> > > > sync_filesystems(1);
> > > > if (unlikely(laptop_mode))
> > > > laptop_sync_completion();
> > > > return 0;
> > > > }
> > > >
> > > > the sync_filesystems(0) is supposed to non-blockingly start IO against
> > > > all devices. It used to do that correctly. But people mucked with it
> > > > so perhaps it no longer does.
> > >
> > > I'm referring to writeback_inodes(). Each invocation of which (to sync
> > > 4MB) will do the same iteration over superblocks A => B => C ... So if
> > > A has dirty pages, it will always be served first.
> > >
> > > So if wbc->bdi == NULL (which is true for kupdate/background sync), it
> > > will have to first exhaust A before going on to B and C.
> >
> > But that works OK. We fill the first device's queue, then it gets
> > congested and sync_sb_inodes() does nothing and we advance to the next
> > queue.
> >
> > If a device has more than a queue's worth of dirty data then we'll
> > probably leave some of that dirty memory un-queued, so there's some
> > lack of concurrency in that situation.
>
> Yes, exactly if block device is not fast enough.

Actually, no.

If there's still outstanding dirty data for any of those queues, both
wb_kupdate() and background_writeout() will take a teeny sleep and then
will re-poll the queues.

Did that logic get broken?


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