Messages in this thread |  | | | Date | Fri, 18 Jan 2008 19:06:28 +0100 | | From | DM <> | | Subject | Re: Why is the kfree() argument const? |
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On Jan 18, 2008 6:02 AM, David Schwartz <davids@webmaster.com> wrote: > > However, *destroying* an object is not a metadata operation -- it destroys > the data as well. This is kind of a philosophical point, but an object does > not have a "does this object exist" piece of metadata. If an object does not > exist, it has no data. So destroying an object destroys the data and is thus > a write/modification operation on the data. >
In C++ you can delete a const pointer. Now I know kernel hackers aren't especially impressed with C++ but maybe someone could look up the rationale for that design decision (I couldn't find it). It might shed some light on this discussion.
/DM
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