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Messages in this thread |
>>>+static inline int pspace_task_visible(struct pspace *pspace, struct
>>
>>task_struct *tsk)
>>
>>>+{
>>>+ return (tsk->pspace == pspace) ||
>>>+ ((tsk->pspace->child_reaper.pspace == pspace) &&
>>>+ (tsk->pspace->child_reaper.task == tsk));
>>
>><<< the logic with child_reaper which can be somehow partly inside pspace... and
>>this check is not that abvious.
>
>
> This is the check for what shows up in /proc.
>
> Given that is how I have explicitly documented things to work, (the
> init process straddles the boundary) I fail to see how it is not obvious.
I was confused by the fact that child_reaper.pspace is actually a parent
pspace.
Kirill
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