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SubjectRe: [PATCH 3/6] i386 virtualization - Make ldt a desc struct
* Zachary Amsden (zach@vmware.com) wrote:
> Chris Wright wrote:
> >>@@ -30,7 +33,7 @@
> >>static inline unsigned long get_desc_base(struct desc_struct *desc)
> >>{
> >> unsigned long base;
> >>- base = ((desc->a >> 16) & 0x0000ffff) |
> >>+ base = (desc->a >> 16) |
> >
> >Seemingly unrelated.
>
> Yes, alas my bucket has leaks. I was hoping for better assembly, but
> never got around to verifying. So I matched this to shorter C code
> which I had obsoleted.

OK.

> >>@@ -28,28 +28,27 @@
> >>}
> >>#endif
> >>
> >>-static inline int alloc_ldt(mm_context_t *pc, const int oldsize, int
> >>mincount, const int reload)
> >>+static inline int alloc_ldt(mm_context_t *pc, const int old_pages, int
> >>new_pages, const int reload)
> >>{
> >>- void *oldldt;
> >>- void *newldt;
> >>+ struct desc_struct *oldldt;
> >>+ struct desc_struct *newldt;
> >>
> >
> >Not quite related here (since change was introduced in earlier patch),
> >but old alloc_ldt special cased when room was available. This is gone,
> >so am I reading this correctly, each time through it will allocate a
> >new one, and free the old one (if it existed)? Just double checking
> >that change doesn't introduce possible mem leak.
> >
>
> Since LDT is now in pages, it is only called when page reservation
> increases. I chose a slightly bad name here for new_pages. See
> further down:
>
> if (page_number >= mm->context.ldt_pages) {

OK, nice, I had missed that.

> error = alloc_ldt(&current->mm->context,
> mm->context.ldt_pages,
> page_number+1, 1);
> if (error < 0)
> goto out_unlock;
> }
>
> I actually had to check the code here to verify there is no leak, and I
> don't believe I changed any semantics, but was very happy when I found this:
>
> if (old_pages) {
> ClearPagesLDT(oldldt, old_pages);
> if (old_pages > 1)
> vfree(oldldt);
> else
> kfree(oldldt);
> }

Yeah, I saw that bit too, so I was assuming it was OK, and wanted to
double-check.

> >>- mincount = (mincount+511)&(~511);
> >>- if (mincount*LDT_ENTRY_SIZE > PAGE_SIZE)
> >>- newldt = vmalloc(mincount*LDT_ENTRY_SIZE);
> >>+ if (new_pages > 1)
> >>+ newldt = vmalloc(new_pages*PAGE_SIZE);
> >> else
> >>- newldt = kmalloc(mincount*LDT_ENTRY_SIZE, GFP_KERNEL);
> >>+ newldt = kmalloc(PAGE_SIZE, GFP_KERNEL);
> >
> >If so, then full page is likely to be reusable in common case, no? (If
> >there's such a thing as LDT common case ;-)
>
> Yeah, there is no LDT common case. This code could be made 100% optimal
> with a lot of likely/unlikely wrappers and additional cleanup, but
> seeing as it is already uncommon, the only worthwhile optimizations for
> this code are ones that reduce code size or make it more readable and
> less error prone. I had to write a test that emits inline assembler
> onto a crossing page boundary, clones the VM, and tests strict
> conformance to byte/page limits to actually test this. :)

Ouch, sounds painful ;-)

> >> if (!newldt)
> >> return -ENOMEM;
> >>
> >>- if (oldsize)
> >>- memcpy(newldt, pc->ldt, oldsize*LDT_ENTRY_SIZE);
> >>+ if (old_pages)
> >>+ memcpy(newldt, pc->ldt, old_pages*PAGE_SIZE);
> >> oldldt = pc->ldt;
> >> if (reload)
> >>- memset(newldt+oldsize*LDT_ENTRY_SIZE, 0,
> >>(mincount-oldsize)*LDT_ENTRY_SIZE);
> >>+ memset(newldt+old_pages*LDT_ENTRIES_PER_PAGE, 0,
> >>(new_pages-old_pages)*PAGE_SIZE);
> >
> >In fact, I _think_ this causes a problem. Who says newldt is bigger
> >than old one? This looks like user-triggerable oops to me.
>
> Safe -- two call sites. One has no LDT (cloning), and the other is here:
>
> if (page_number >= mm->context.ldt_pages) {

Yes, thanks, as I mentioned above, that's what I was missing.

> error = alloc_ldt(&current->mm->context,
> mm->context.ldt_pages,
>
> Note page_number is zero-based, ldt_pages is not.
>
> >>@@ -113,13 +114,13 @@
> >> unsigned long size;
> >> struct mm_struct * mm = current->mm;
> >>
> >>- if (!mm->context.size)
> >>+ if (!mm->context.ldt_pages)
> >> return 0;
> >> if (bytecount > LDT_ENTRY_SIZE*LDT_ENTRIES)
> >> bytecount = LDT_ENTRY_SIZE*LDT_ENTRIES;
> >>
> >> down(&mm->context.sem);
> >>- size = mm->context.size*LDT_ENTRY_SIZE;
> >>+ size = mm->context.ldt_pages*PAGE_SIZE;
> >> if (size > bytecount)
> >> size = bytecount;
> >
> >This now looks like you can leak data? Since full page is unlikely
> >used, but accounting is done in page sizes. Asking to read_ldt with
> >bytcount of PAGE_SIZE could give some uninitialzed data back to user.
> >Did I miss the spot where this is always zero-filled?
>
> You could leak data, but the code already takes care to zero the page.
> This is especially important, since random present segments could allow
> a violation of kernel security ;)

Right, good point.

> if (reload)
> memset(newldt+old_pages*LDT_ENTRIES_PER_PAGE, 0,
> (new_pages-old_pages)*PAGE_SIZE);

Ah, I misread reload as being same arg as oldmode in write_ldt(), so
had myself thinking that was user controlled.

> Wow. Thanks for a completely thorough review. I have tested this code
> quite intensely, but I very much appreciate having more eyes on it,
> since it is quite a tricky biscuit.

Agreed, the more eyes the better.

thanks,
-chris
-
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