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Subject[patch 5/9] block/pf: replace pf_sleep() with msleep_interruptible()
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Any comments would be appreciated. This is a re-push of a patch I
submitted 20 July which hasn't been merged as of
2.6.9-rc1-mm5/2.6.9-rc2.

Description: msleep_interruptible() is used instead of pf_sleep()
to guarantee the task delays as expected. The defintion of pf_sleep()
is also removed.

Signed-off-by: Nishanth Aravamudan <nacc@us.ibm.com>

Signed-off-by: Maximilian Attems <janitor@sternwelten.at>
---

linux-2.6.9-rc2-bk7-max/drivers/block/paride/pf.c | 10 ++--------
1 files changed, 2 insertions(+), 8 deletions(-)

diff -puN drivers/block/paride/pf.c~msleep_interruptible-drivers_block_pf drivers/block/paride/pf.c
--- linux-2.6.9-rc2-bk7/drivers/block/paride/pf.c~msleep_interruptible-drivers_block_pf 2004-09-21 21:07:53.000000000 +0200
+++ linux-2.6.9-rc2-bk7-max/drivers/block/paride/pf.c 2004-09-21 21:07:53.000000000 +0200
@@ -526,12 +526,6 @@ static void pf_eject(struct pf_unit *pf)

#define PF_RESET_TMO 30 /* in tenths of a second */

-static void pf_sleep(int cs)
-{
- current->state = TASK_INTERRUPTIBLE;
- schedule_timeout(cs);
-}
-
/* the ATAPI standard actually specifies the contents of all 7 registers
after a reset, but the specification is ambiguous concerning the last
two bytes, and different drives interpret the standard differently.
@@ -546,11 +540,11 @@ static int pf_reset(struct pf_unit *pf)
write_reg(pf, 6, 0xa0+0x10*pf->drive);
write_reg(pf, 7, 8);

- pf_sleep(20 * HZ / 1000);
+ msleep_interruptible(20);

k = 0;
while ((k++ < PF_RESET_TMO) && (status_reg(pf) & STAT_BUSY))
- pf_sleep(HZ / 10);
+ msleep_interruptible(100);

flg = 1;
for (i = 0; i < 5; i++)
_
-
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