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    SubjectRe: asm (lidt) question
    Davide Libenzi wrote:
    > IMHO, since "var" is really an output parameter.

    "var" is read, not written.
    I think you are confusing "lidt" with "sidt".

    Therefore

    > __asm__ __volatile__("lidt %0": :"m" (var));

    is the better choice, and that's why I wrote it in reboot.c :)

    -- Jamie
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