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    SubjectRe: Question about sched_yield()

    On Tue, 18 Jun 2002 18:45:55 -0400, Stevie O wrote:

    >At 11:00 AM 6/18/2002 -0700, David Schwartz wrote:

    >>This is the same error repeated again. Since you realize that an endless
    >>loop on sched_yield is *not* equivalent to blocking, why do you then say
    >>"in
    >>fact doing useful work"? By what form of ESP is the kernel supposed to
    >>determine that the sched_yield task is not 'doing useful work' and the
    >>other
    >>task is?

    >By this form of ESP: sched_yield() means "I have nothing better to do right
    >now, give my time to someone who does". If a thread is doing useful work,
    >why would it call sched_yield() ?!?

    To give other threads a chance to do useful work too, perhaps because it
    just released a mutex that other threads might need that it held for an
    unusually long time.

    DS


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