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SubjectRe: Question about sched_yield()

On Tue, 18 Jun 2002 18:45:55 -0400, Stevie O wrote:

>At 11:00 AM 6/18/2002 -0700, David Schwartz wrote:

>>This is the same error repeated again. Since you realize that an endless
>>loop on sched_yield is *not* equivalent to blocking, why do you then say
>>"in
>>fact doing useful work"? By what form of ESP is the kernel supposed to
>>determine that the sched_yield task is not 'doing useful work' and the
>>other
>>task is?

>By this form of ESP: sched_yield() means "I have nothing better to do right
>now, give my time to someone who does". If a thread is doing useful work,
>why would it call sched_yield() ?!?

To give other threads a chance to do useful work too, perhaps because it
just released a mutex that other threads might need that it held for an
unusually long time.

DS


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