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    SubjectRe: Question about sched_yield()
    At 11:00 AM 6/18/2002 -0700, David Schwartz wrote:
    >This is the same error repeated again. Since you realize that an endless
    >loop on sched_yield is *not* equivalent to blocking, why do you then say "in
    >fact doing useful work"? By what form of ESP is the kernel supposed to
    >determine that the sched_yield task is not 'doing useful work' and the other
    >task is?

    By this form of ESP: sched_yield() means "I have nothing better to do right now, give my time to someone who does". If a thread is doing useful work, why would it call sched_yield() ?!?


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