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SubjectRe: [Lse-tech] Re: NUMA scheduler (was: 2.5 merge candidate list 1.5)
>> Michael, the way I read the NR_CPUS loop, you walk every cpu
>> in the system, and take the best from all of them. In which case
>> what's the point of the last_exec_cpu stuff? On the other hand,
>> I changed your NR_CPUS to 4 (ie just walk the cpus in that node),
>> and it got worse. So perhaps I'm just misreading your code ...
>> and it does seem significantly cheaper to execute than Erich's.
>>
> You are reading it correct. The only thing that the last_exec_cpu
> does is to help spread the load across nodes. Without that what was
> happening is that node 0 would get completely loaded, then node 1,
> etc. With it, in cases where one or more runqueues have the same
> length, the one chosen tends to get spread out a bit. Not the
> greatest solution, but it helps.

OK. I made a simple boring optimisation to your patch. Shaved almost
a second off system time for kernbench, and seems idiotproof to me,
shouldn't change anything apart from touching fewer runqueues: if
we find a runqueue with nr_running == 0, stop searching ... we ain't
going to find anything better ;-)

Kernbench:
Elapsed User System CPU
2.5.44-mm4 19.676s 192.794s 42.678s 1197.4%
2.5.44-mm4-hbaum-1 19.746s 189.232s 38.354s 1152.2%
2.5.44-mm4-hbaum-12 19.322s 190.176s 40.354s 1192.6%
2.5.44-mm4-hbaum-12-firstzero 19.292s 189.66s 39.428s 1187.4%

Patch is probably space-eaten, so just whack it in by hand.

--- 2.5.44-mm4-hbaum-12/kernel/sched.c 2002-10-27 19:54:25.000000000 -0800
+++ 2.5.44-mm4-hbaum-12-first_low/kernel/sched.c 2002-10-27 16:42:10.000000000 -0800
@@ -2206,6 +2206,8 @@
if (minload > cpu_rq(cur_cpu)->nr_running) {
minload = cpu_rq(cur_cpu)->nr_running;
best_cpu = cur_cpu;
+ if (minload == 0)
+ break;
}
if (++cur_cpu >= NR_CPUS)
cur_cpu = 0;
-
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