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SubjectRe: PID of init != 1 when initrd with pivot_root
> > Well, I upgraded and found pivot_root and the problem is that how do I make init
> > run with PID 1. My linuxrc gets PID 7.
> >
> > 1 ? 00:03:05 swapper
> > 2 ? 00:00:00 keventd
> > 3 ? 00:00:00 kswapd
> > 4 ? 00:00:00 kreclaimd
> > 5 ? 00:00:00 bdflush
> > 6 ? 00:00:00 kupdated
> > 7 ? 00:00:00 linuxrc
> >
> > init doesn't like running with any other PID than 1. I could probably revert to
> > the not so old way of doing things and exit linuxrc and let the kernel change
> > root. But then I wouldn't be able to mount root over samba :-(. ( not that I
> > have any samba shares :-)
>
> This is this way for backwards bug compatibility. Use the following
> command line options to make it behave properly:
>
> ram=/dev/ram0 init=/linuxrc

That's what I did, almost. I think you meant root=/dev/rd/0 init=/linuxrc ( with
devfs) though init parameter is made redundant by the new "root change
mechanism" pivot_root.

But the problem still remains. How do I make my /sbin/init run with PID 1 using
initial ramdisk under the new root change mechanism? I don't want to use the old
change_root mechanism since the Documentation/initrd.txt says:

Obsolete root change mechanism
------------------------------
The following mechanism was used before the introduction of pivot_root.
Current kernels still support it, but you should _not_ rely on its
continued availability.
...
This old, deprecated mechanism is commonly called "change_root", while
the new, supported mechanism is called "pivot_root".

--
Ivan Vadovic
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