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SubjectRe: Is this a kernel problem? segmentation fault
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"Donald Harter" <dharter@lycos.com> writes:

|> I started by debugging this program where I was getting a
|> segmentation fault. I used gdb and traced the bug to a call
|> instruction. I dissasembled the code and stepped through the
|> instructions. The program got a segmentation fault when it
|> executed an assembly language call instruction. Using gdb I was
|> able to disassemble the instructions at the called address. Why
|> can gdb disasemble instructions at a call address and a call to
|> that address fails with a segmentation fault?

Perhaps a stack overflow, or stack pointer is pointing to lala land.

Andreas.

--
Andreas Schwab "And now for something
Andreas.Schwab@suse.de completely different."
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