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    SubjectRe: Is this a kernel problem? segmentation fault
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    "Donald Harter" <dharter@lycos.com> writes:

    |> I started by debugging this program where I was getting a
    |> segmentation fault. I used gdb and traced the bug to a call
    |> instruction. I dissasembled the code and stepped through the
    |> instructions. The program got a segmentation fault when it
    |> executed an assembly language call instruction. Using gdb I was
    |> able to disassemble the instructions at the called address. Why
    |> can gdb disasemble instructions at a call address and a call to
    |> that address fails with a segmentation fault?

    Perhaps a stack overflow, or stack pointer is pointing to lala land.

    Andreas.

    --
    Andreas Schwab "And now for something
    Andreas.Schwab@suse.de completely different."
    SuSE Labs, SuSE GmbH, Schanzäckerstr. 10, D-90443 Nürnberg
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