Messages in this thread | | | From | "Khimenko Victor" <> | Date | Thu, 17 Feb 2000 03:54:48 +0300 (MSK) | Subject | Re: #! and argv[0]: the path is removed before invoking the interpreter |
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In <AA5Qpguad0@khim.sch57.msk.ru> alan@lxorguk.ukuu.org.uk (alan@lxorguk.ukuu.org.uk) wrote: > In <E12LBjK-0000Xp-00@the-village.bc.nu> Alan Cox (alan@lxorguk.ukuu.org.uk) wrote: >>> I believe the behavior of #! on Solaris goes all the way back to BSD >>> in of the early 80's. FreeBSD 3.0 behaves as Solaris does. >>> >>> I hope this considered a bug. If there willingness to take a patch for >>> it, I might work on making the fix.
>> Im not sure about bug, but its certainly worth behaving the same way as >> everyone else in this case if its appropriate to do so. Take a look at >> the fs/binfmt* code and sure - send a patch
> IMO it's better be CONSISTENT. Either > 1) argv[0] is always the same thing that was passed to execv > or > 2) argv[0] is always "realpath" to executable.
> Since in case of "real binary" we doing 1) IMNSHO we should do this in case > of script as well...
Oops. Sorry, of course here natural thing is to use exactly what was fater #! : execve() is such case sits deep in kernel and natural argument is of course full speciafied name :-/
P.S. But limtation for just ONE additional argument looks ugly :-( Even if it's like Unix always worked :-((
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