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    SubjectRe: fork() Problem?
    On Wed, 5 May 1999, Yavuz Selim Komur wrote:

    > On Tue, 4 May 1999, David Miller wrote:
    > >
    > > You do not initialize the "status" variable passed to wait(), this is
    > > probably why it crashes on SunOS. "status" could contain anything,
    > > any value, and probably it contains garbage or a wild pointer.
    > Execuse me. I didn't well defined my problem. SegFault? ignore it.
    > Problem is sequence error.
    > if (pid = fork())
    ^^^^________ logical test of an assignment? This will always
    be true!
    if((pid = fork()) != 0) or
    if((pid = fork()))
    You need to make the assignment first, then
    test for non-zero.

    > printf("Main Program");
    > else
    > printf("Child Program");
    > it's clear?

    No, also if you want a defined order in which stuff is printed either
    do fprintf(stderr, "whatever"); or printf("whatever"); fflush(stdout);

    Standard output is buffered.

    This works fine, and in the correct order.

    #include <stdio.h>
    #include <stdlib.h>
    #include <unistd.h>
    #include <wait.h>

    int main(void);
    int main()
    pid_t pid;
    int status;

    switch((pid = fork()))
    case 0: /* Child */
    fprintf(stderr,"Child (%ld)\n", getpid());
    case -1:
    fprintf(stderr, "Error with fork()\n");
    default: /* Parent */
    fprintf(stderr, "Parent waits for child (%ld) status\n", pid);
    fprintf(stderr, "Child's exit status was %d\n", status >> 8);
    return 0;

    Dick Johnson
    Penguin : Linux version 2.2.6 on an i686 machine (400.59 BogoMips).
    Warning : It's hard to remain at the trailing edge of technology.

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