Messages in this thread | | | Date | Fri, 9 Apr 1999 16:28:12 -0400 (EDT) | From | Alexander Viro <> | Subject | Re: Kernel Stack |
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On Fri, 9 Apr 1999, Richard B. Johnson wrote:
> Read Brian Gerst's response. My whole point was that interrupts are > not associated with a user process, which I have shown. If the designer > decided to use a portion of some kernel element as an interrupt stack If? Since interrupts may happen when you are within ring 0 you have no choice other than allow them to use the current kernel stack. And code the kernel stuff allowing that possibilty.
> it does not change this essential fact. The user processes` stack is > not even used for the return address of the interrupt so the user's > stack-pointer is never touched at all.
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