Messages in this thread |  | | | Date | Tue, 11 Mar 1997 08:36:12 -0500 (EST) | | From | "Richard B. Johnson" <> | | Subject | Re: 2.0.30 - its all a numbers game, I tell ya! |
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On Tue, 11 Mar 1997, Taner Halicioglu wrote:
> On Tue, 11 Mar 1997, Chairudin S. Harjo wrote: > > > Tony Knight wrote: > > > > > 2 * 1 + 0 = 2 + 0 / 30 > > 2 * 1 / 0 = 2 . 0 . 30 > > > > This one is wrong!!! > > Any number divided by 0 is infinite. > > So...the left side is infinite, the right side is not. > > no. Any non-zero number divided by zero results in an infinite answer. > 0/0, however, is strictly "undefined". > > 3/0 = X is the same as X*0 = 3, thus X=infinity > > 0/0 = X is the same as X*0 = 0, thus X can be ANY number (thus, > undefined).
Since you asked..... Since this continues.... N/N = 1 For all N Therefore: 0/0 = 1 Proof: (actually a conjecture) Numbers from -N to +N are LINER, there is no discontinuity through zero. Therefore: +N/+N = 1 -N/-N = 1 And everything in between... (-.000000000000001 N) / (-.000000000000001 N) = 1 ........... ........... All real numbers in between (lots) ........... (+.000000000000001 N) / (+.000000000000001 N) = 1 All the real numbers between - N and + N, when divided by themselves must equal 1. Therefore 0/0 = 1.
Now, if N was infinity, and it was divided by the same N, it too would equal 1. However, one must be sure that it is the same infinity from the same set. You can't be too sure about that because a number series converges at infinity losing some properties in the process. If N was infinity.... N + N = N N * N = N N - N should = 0, but maybe not. N / N should be 1, but maybe not. Such a problem does not exist at zero, therefore the proof stands.
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